0=50+73t-3t^2

Solution for 0=50+73t-3t^2 equation:

0=50+73t-3t^2

We move all terms to the left:

0-(50+73t-3t^2)=0

We add all the numbers together, and all the variables

-(50+73t-3t^2)=0

We get rid of parentheses

3t^2-73t-50=0

a = 3; b = -73; c = -50;
Δ = b2-4ac
Δ = -732-4·3·(-50)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-77}{2*3}=\frac{-4}{6}
=-2/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+77}{2*3}=\frac{150}{6}
=25
$